Solving problems with constraints — when equations aren't enough, inequalities show the range of possibilities
"Mathematics is the art of saying many things in many different ways." — Maxwell
In earlier classes, you learned to solve equations. But what about statements like "the height of all students is less than 160 cm" or "the classroom can hold at most 60 tables"? These use inequality symbols instead of equals signs.
a < b means a is strictly less than b. Example: 3 < 5
a > b means a is strictly greater than b. Example: 7 > 5
a ≤ b means a is less than or equal to b. Example: x ≤ 4
a ≥ b means a is greater than or equal to b. Example: x ≥ 3
Numerical inequalities: 3 < 5, 7 > 5
Literal inequalities: x < 5, y > 2, x ≥ 3
Double inequalities: 3 < x < 5 (x is between 3 and 5)
Linear inequalities in one variable: ax + b < 0, ax + b ≥ 0
Linear inequalities in two variables: ax + by < c, ax + by ≥ c
Strict inequalities: Use < or > (no equality)
Slack inequalities: Use ≤ or ≥ (includes equality)
• Ravi has ₹200 and rice costs ₹30/kg: 30x < 200 (where x = kg bought)
• Reshma has ₹120 for registers (₹40) and pens (₹20): 40x + 20y ≤ 120
• Temperature must stay between 30°C and 35°C: 30 < C < 35
Solving inequalities is similar to solving equations, but with one critical difference when multiplying or dividing by negative numbers.
You can add or subtract the same number from both sides without changing the inequality sign.
If x > 3, then x + 5 > 3 + 5, so x + 5 > 8
If x ≤ 7, then x - 2 ≤ 7 - 2, so x - 2 ≤ 5
By a POSITIVE number: Sign stays the same
If x > 3, then 2x > 6 ✓
By a NEGATIVE number: Sign REVERSES!
If x > 3, then -2x < -6 (sign flipped from > to <)
Why? Because 3 > 2, but -3 < -2. Multiplying by negative flips the order.
Think of it like a seesaw: multiplying by a negative number flips the seesaw, so the heavier side goes up instead of down!
Now let's solve some linear inequalities step by step.
Step 1: Divide both sides by 30 (positive, so sign stays):
x < 200/30
x < 20/3 ≈ 6.67
Solution: All real numbers less than 20/3
Interval notation: x ∈ (-∞, 20/3)
Step 1: Subtract 3x from both sides:
2x - 3 < 1
Step 2: Add 3 to both sides:
2x < 4
Step 3: Divide by 2:
x < 2
Solution: x ∈ (-∞, 2)
Step 1: Subtract 6x from both sides:
-2x + 3 < 7
Step 2: Subtract 3:
-2x < 4
Step 3: Divide by -2 (REVERSE the sign!):
x > -2
Solution: x ∈ (-2, ∞)
Step 1: Cross-multiply (both denominators positive):
5(5-2x) ≤ 3(x-6)
Step 2: Expand:
25 - 10x ≤ 3x - 18
Step 3: Combine like terms:
-13x ≤ -43
Step 4: Divide by -13 (REVERSE sign):
x ≥ 43/13 ≈ 3.31
Solution: x ∈ [43/13, ∞)
This is two inequalities combined:
-8 ≤ 5x - 3 AND 5x - 3 < 7
Solve both simultaneously:
-8 + 3 ≤ 5x < 7 + 3
-5 ≤ 5x < 10
-1 ≤ x < 2
Solution: x ∈ [-1, 2)
Inequalities can be shown on a number line using circles and shading.
Use for < or > (strict inequality). The number itself is NOT included.
Use for ≤ or ≥ (slack inequality). The number itself IS included.
x < a or x ≤ a: Shade LEFT of a (smaller numbers)
x > a or x ≥ a: Shade RIGHT of a (larger numbers)
| Inequality | Circle | Shade |
|---|---|---|
| x < 3 | Open at 3 | Left |
| x ≥ -2 | Closed at -2 | Right |
| -1 ≤ x < 5 | Closed at -1, Open at 5 | Between |
Inequalities are powerful tools for solving real-world problems with constraints.
A student scored 62 and 48 in two tests. What's the minimum score needed in the third test to average at least 60?
Solution:
Let x = marks in third test
Average ≥ 60
(62 + 48 + x)/3 ≥ 60
110 + x ≥ 180
x ≥ 70
Answer: Minimum 70 marks needed
Find all pairs of consecutive odd natural numbers, both > 10, with sum < 40.
Solution:
Let x = smaller odd number, then x + 2 = larger
x > 10 AND x + (x+2) < 40
x > 10 AND 2x + 2 < 40
x > 10 AND x < 19
So 10 < x < 19. Odd numbers in this range: 11, 13, 15, 17
Answer: Pairs are (11,13), (13,15), (15,17), (17,19)
Keep a solution between 30°C and 35°C. What's the range in Fahrenheit?
Formula: C = (5/9)(F - 32)
Solution:
30 < C < 35
30 < (5/9)(F - 32) < 35
54 < F - 32 < 63
86 < F < 95
Answer: Between 86°F and 95°F
600L of 12% acid solution. How much 30% solution to add so mixture is 15-18% acid?
Solution:
Let x = liters of 30% solution
Total mixture = x + 600 liters
For > 15%: 0.30x + 0.12(600) > 0.15(x + 600)
→ 30x + 7200 > 15x + 9000 → 15x > 1800 → x > 120
For < 18%: 0.30x + 0.12(600) < 0.18(x + 600)
→ 30x + 7200 < 18x + 10800 → 12x < 3600 → x < 300
Answer: 120 < x < 300 liters
• Inequality symbols: < (less), > (greater), ≤ (less or equal), ≥ (greater or equal)
• Rule 1: Add/subtract same number on both sides — sign unchanged
• Rule 2: Multiply/divide by positive — sign unchanged. By negative — sign REVERSES
• Graphing: Open circle for < or >, closed circle for ≤ or ≥
• Shading: Left for less than, right for greater than
• Double inequality: Solve both parts simultaneously
• Word problems: Translate constraints into inequalities, then solve